题目
求所确定的隐函数y= y(x)的导数dy/dx
(x^2)y - lny = x
(x^2)y - lny = x
提问时间:2020-08-01
答案
(x^2)y - lny = x
2x*y+x^2*y'-1/y*y'=1
(x^2-1/y)*y'=1-2xy
y'=(1-2xy)/(x^2-1/y)
2x*y+x^2*y'-1/y*y'=1
(x^2-1/y)*y'=1-2xy
y'=(1-2xy)/(x^2-1/y)
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