题目
[8abˆ(1/3)-b(4/3)]/[4a^(2/3)+2(ab)^(1/3)+b^(2/3下面的
[8abˆ(1/3)-b(4/3)]/[4a^(2/3)+2(ab)^(1/3)+b^(2/3)]÷{[2(a/b)ˆ(1/3)]-1}﹡[bˆ(1/3)]
[8abˆ(1/3)-b(4/3)]/[4a^(2/3)+2(ab)^(1/3)+b^(2/3)]÷{[2(a/b)ˆ(1/3)]-1}﹡[bˆ(1/3)]
提问时间:2020-07-27
答案
[8abˆ(1/3)-b(4/3)]/[4a^(2/3)+2(ab)^(1/3)+b^(2/3)]÷{[2(a/b)ˆ(1/3)]-1}﹡[bˆ(1/3)]
=[8ab^(1/3)-b^(4/3)]/[4a^(2/3)+2(ab)^(1/3)+b^(2/3)]×{[b^(1/3)]/2a^(1/3)-b^(1/3)}×b^(1/3)
=[8ab^(1/3)-b^(4/3)]/[4a^(2/3)+2(ab)^(1/3)+b^(2/3)]×[b^(2/3)]/2a^(1/3)-b^(1/3)
=(8ab-b^2)/[8a+4a^(2/3)b^(1/3)+2a^(1/3)b^(2/3)-4a^(2/3)b^(1/3)-2a^(1/3)b^(2/3)-b
=(8ab-b^2)/(8a-b)
=b
=[8ab^(1/3)-b^(4/3)]/[4a^(2/3)+2(ab)^(1/3)+b^(2/3)]×{[b^(1/3)]/2a^(1/3)-b^(1/3)}×b^(1/3)
=[8ab^(1/3)-b^(4/3)]/[4a^(2/3)+2(ab)^(1/3)+b^(2/3)]×[b^(2/3)]/2a^(1/3)-b^(1/3)
=(8ab-b^2)/[8a+4a^(2/3)b^(1/3)+2a^(1/3)b^(2/3)-4a^(2/3)b^(1/3)-2a^(1/3)b^(2/3)-b
=(8ab-b^2)/(8a-b)
=b
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