题目
因式分解(x-1)(x+2)(x+3)(x+6)-13
提问时间:2020-06-19
答案
(x-1)(x+2)(x+3)(x+6)-13
=(x-1)(x+6)(x+2)(x+3)-13
=(x²+5x-6)(x²+5x+6)-13
=(x+5x)²-36-13
=(x+5x)²-49
=(x+5x+7)(x+5x-7)
=(x-1)(x+6)(x+2)(x+3)-13
=(x²+5x-6)(x²+5x+6)-13
=(x+5x)²-36-13
=(x+5x)²-49
=(x+5x+7)(x+5x-7)
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