题目
题型:填空题难度:一般来源:不详
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084857-32619.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084857-76296.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084858-78148.png)
答案
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084858-65482.png)
解析
试题分析:根据题意由于集合
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084857-32619.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084857-76296.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084858-78148.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084858-65482.png)
点评:主要是考查了集合的并集的运算,属于基础题 。
核心考点
举一反三
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084855-41369.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084855-87381.png)
A.
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084856-75768.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084856-80396.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084856-14989.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084856-19927.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084853-92956.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084853-31300.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084854-26824.png)
A.![]() | B.![]() | C.![]() | D.![]() |
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084851-63872.png)
A.![]() | B.![]() |
C.![]() | D.R |
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084850-36481.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084850-55197.png)
A.0 | B.1 | C.2 | D.不确定 |
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084847-75482.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084847-75158.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084847-74881.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084847-84708.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084848-47948.png)
(i)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084848-91063.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084848-14655.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084848-96264.png)
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084848-65280.png)
那么称这两个集合“保序同构”.现给出以下3对集合:
①
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084849-15841.png)
②
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084849-43045.png)
③
![](http://img.shitiku.com.cn/uploads/allimg/20190817/20190817084849-16391.png)
其中,“保序同构”的集合对的序号是____________(写出所有“保序同构”的集合对的序号)
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