题目
题型:不详难度:来源:
A.CD、EF、GH | B.AB、CD.EF | C.AB、CD、GH | D.AB、EF、GH |
答案
22+42 |
5 |
1+4 |
5 |
13 |
(
5 |
13 |
5 |
B、∵AB=2
2 |
5 |
5 |
(
5 |
2 |
5 |
C、∵AB=2
2 |
5 |
13 |
(2
2 |
13 |
5 |
D、∵AB=2
2 |
5 |
13 |
(2
2 |
5 |
13 |
故选:D.
核心考点
试题【如图,正方形组成的网格中标出了AB、CD、EF、GH四条线段,其中能构成一个直角三角形三边的线段是( )A.CD、EF、GHB.AB、CD.EFC.AB、CD】;主要考察你对勾股定理逆定理等知识点的理解。[详细]
举一反三
(1)试判断△ABC的形状,并说明理由;
(2)若S△MNP=3S△NOP,
①求sinB的值;
②判断△ABC的三边长能否取一组适当的值,使△MND是等腰直角三角形?如能,请求出这组值;如不能,请说明理由.
A.∠A+∠B=∠C | B.∠A:∠B:∠C=1:3:2 | ||||||
C.(b+c)(b-c)=a2 | D.a=
|
A.4,5,6 | B.2,2
| C.6,8,11 | D.5,12,17 |
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