题目
题型:不详难度:来源:
![](http://img.shitiku.com.cn/uploads/allimg/20191017/20191017091743-89818.png)
答案
![](http://img.shitiku.com.cn/uploads/allimg/20191017/20191017091743-85850.png)
解析
试题分析:设反比例函数的解析式为
![](http://img.shitiku.com.cn/uploads/allimg/20191017/20191017091744-37690.png)
因为矩形ABOC的面积为3,所以|k|=3,
所以k=±3,
由图象在第二象限,
所以k<0,;k=-3,所以这个反比例函数解析式为
![](http://img.shitiku.com.cn/uploads/allimg/20191017/20191017091743-85850.png)
核心考点
举一反三
![](http://img.shitiku.com.cn/uploads/allimg/20191017/20191017091739-33380.png)
(1)直接写出B、C、D三点的坐标;
(2)若将矩形向下平移,矩形的两个顶点恰好同时落在反比例函数的图象上,猜想这是哪两个点,并求矩形的平移距离和反比例函数的解析式.
A.(2,3) | B.(3,2) | C.(-3,2) | D.(6,1) |
![](http://img.shitiku.com.cn/uploads/allimg/20191017/20191017091724-56397.png)
A.y1<y2<0 | B.y2<0<y1 | C.y1<0<y2 | D.y2<y1<0 |
![](http://img.shitiku.com.cn/uploads/allimg/20191017/20191017091714-24805.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191017/20191017091715-53789.png)
A.3 | B.-3 | C.-6 | D.6 |
![](http://img.shitiku.com.cn/uploads/allimg/20191017/20191017091708-15900.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191017/20191017091708-53595.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191017/20191017091709-59395.png)
![](http://img.shitiku.com.cn/uploads/allimg/20191017/20191017091709-90275.png)