题目
题型:填空题难度:一般来源:不详
答案
当n=-1且n+3为偶数,即n=-1时,nn+3-1=0成立;
当n≠0且n+3=0,即n=-3时,nn+3-1=0成立.
故答案为:1或-1或-3.
核心考点
举一反三
2+y |
A.1 | B.-1 | C.2012 | D.-2012 |
8 |
2 |
1 | ||
|
3 |
|
A.-2 | B.4或-2 | C.4 | D.4或2 |
A.x3+x3=x6 | B.x3+x3=x9 | C.x3•x3=x6 | D.x3•x3=x9 |
2+y |
A.1 | B.-1 | C.2012 | D.-2012 |
8 |
2 |
1 | ||
|
3 |
|
A.-2 | B.4或-2 | C.4 | D.4或2 |
A.x3+x3=x6 | B.x3+x3=x9 | C.x3•x3=x6 | D.x3•x3=x9 |